is the area of a circle sector, like a slice of pie.
(1/2)×sin(θ)×side1×side2
is the side-angle-side formula for the area of a triangle.
We know that the triangle encompassed by the sector has two sides that are equal to the radius, so we replace side1×side2 with r^2. Since the area of the arc segment is equal to the area of a sector minus the triangle, we can subtract triangle area from sector area to get
(1/2)×(θ-sin(θ))×r^2
which is the area of the arc segment, as shown with pie in the picture.
Theta minus sin theta? What does that give you
is the area of a circle sector, like a slice of pie.
is the side-angle-side formula for the area of a triangle.
We know that the triangle encompassed by the sector has two sides that are equal to the radius, so we replace side1×side2 with r^2. Since the area of the arc segment is equal to the area of a sector minus the triangle, we can subtract triangle area from sector area to get
which is the area of the arc segment, as shown with pie in the picture.
Is theta in radians? That’s the only way I see this working
Yeah, it’s in radians. The degree version has a less clean format.
That makes way more sense, I was so confused, cheers
Kepler’s Equation
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